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+--- Thread: Does this work? (/Thread-Does-this-work.html)
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Does this work? - Pozzuh - 09-21-2011
@AZUMIKKEL doesn't think this piece of code works and I'm trolling.
So I'm making a poll to measure who thinks it does and who doesn't.
Code:
randomFunc()
{
if((13 & 37) == 5)
iPrintLnBold("It works! :)");
}edit: move to rage section if necessary.
Disclaimer:
This is a
Quote:thats like saying "LOL guys, he did this, and he's stupid, you're with me right? lets vote" in a real life scenario with 8 year oldspost. But i'm bored and feel no shame.
RE: Does this work? - iAegle - 09-21-2011
It probably works .. but do you know what it does/checks?
RE: Does this work? - JariZ - 09-21-2011
it won't work, you should use 13 + 37
RE: Does this work? - Nekochan - 09-21-2011
Lol,
its like
Code:
1337_hax = (13+37);
if(randomInt(1337_hax) == 5)
{
iprintLn("1337 Modding");
}RE: Does this work? - Tomsen1410 - 09-21-2011
It works but do u know what? : P
RE: Does this work? - SuperNovaAO - 09-21-2011
(09-21-2011, 18:14)jariz Wrote: it won't work, you should use 13 + 37
Facepalm
RE: Does this work? - Pozzuh - 09-21-2011
but 13 + 37 is not 5
RE: Does this work? - iAegle - 09-21-2011
(09-21-2011, 19:52)SuperNovaAO Wrote:(09-21-2011, 18:14)jariz Wrote: it won't work, you should use 13 + 37
Facepalm
So basicly it means that both of the values have to be true to continue?
since 0 is false and 1 < is true .. I guess this will work?
RE: Does this work? - Pozzuh - 09-21-2011
As I understand it, it works like this
00101011 = 83
00000111 = 15
00000011 = 3
Both numbers have the last 1s in common.
RE: Does this work? - SuperNovaAO - 09-21-2011
(09-21-2011, 19:59)Pozzuh Wrote: As I understand it, it works like this
00101011 = 83
00000111 = 15
00000011 = 3
Both numbers have the last 1s in common.
Yes, this is how a CPU sees it. No idea if it's implemented properly in CoDScript.
Just that we were talking about 13 and 37.
001101 = 13
100101 = 37
--------------------------
000101 = 5
The default Mac OS X and Windows XP+ calculators do this right btw.